Details
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New Feature
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Resolution: Fixed
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Major
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8.2-milestone-2
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None
Description
We have a method to quote the pattern:
$regextool.quote($stringLiteral)
We need a method to quote the replacement string:
#set ($out = $out.replaceAll(" (id|for)=('|"")$regextool.quote($oldId)", " ${escapetool.d}1=${escapetool.d}2$regextool.quoteReplacement($newId)"))
Attachments
Issue Links
- blocks
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XWIKI-13528 Add support for replacing the default WYSIWYG editor
- Closed